QUESTION IMAGE
Question
solve for x. round to the nearest tenth, if necessary.
answer attempt 1 out of 2
x =
Step1: Use trigonometric ratio
In right - triangle \( \triangle RQP\), \(\cos R=\frac{QR}{RP}\). Given \( \angle R = 19^{\circ}\), \(QR = 7.6\), and \(RP=x\).
So, \(\cos(19^{\circ})=\frac{7.6}{x}\).
Step2: Solve for \(x\)
Rearrange the formula to \(x=\frac{7.6}{\cos(19^{\circ})}\).
We know that \(\cos(19^{\circ})\approx0.9455\).
Then \(x=\frac{7.6}{0.9455}\approx8.0\).
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\(8.0\)