Question

8.6 solve radical equations (homework)
score: 1/16 answered: 1/16
question 2
find all real solutions:
\\(\sqrt{2a - 1}=3\\)
\\(a =\\) . (if no solution exists, enter dne)

Explanation:

Step1: Square both sides

$(\sqrt{2a - 1})^2=3^2$
$2a - 1 = 9$

Step2: Solve for a

Add 1 to both sides: $2a=9 + 1$, so $2a = 10$.
Divide both sides by 2: $a=\frac{10}{2}=5$

Answer:

$5$