Question

solve the inequality.
$3x > -30$
\\(\circ\\) a \\(x < -10\\)
\\(\circ\\) b \\(x > -90\\)
\\(\circ\\) c \\(x > -10\\)

question 11 (1 point)
solve the inequality.
$3x - 5 > 10$
\\(\circ\\) a \\(x < 5\\)
\\(\circ\\) b \\(x > 5\\)
\\(\circ\\) c \\(x > \frac{5}{3}\\)
\\(\circ\\) d \\(x < \frac{5}{3}\\)

Explanation:

First Inequality ($3x > -30$)

Step1: Divide both sides by 3

To solve for \( x \), we divide both sides of the inequality \( 3x > -30 \) by 3. Since 3 is a positive number, the direction of the inequality sign remains the same.

$$ \frac{3x}{3} > \frac{-30}{3} $$

Step2: Simplify both sides

Simplifying the left side gives \( x \), and simplifying the right side gives \( -10 \). So we have:

$$ x > -10 $$

Step1: Add 5 to both sides

To isolate the term with \( x \), we add 5 to both sides of the inequality \( 3x - 5 > 10 \).

$$ 3x - 5 + 5 > 10 + 5 $$

Step2: Simplify both sides

Simplifying the left side gives \( 3x \), and simplifying the right side gives \( 15 \). So we have:

$$ 3x > 15 $$

Step3: Divide both sides by 3

Now we divide both sides by 3 (a positive number, so the inequality sign remains the same) to solve for \( x \).

$$ \frac{3x}{3} > \frac{15}{3} $$

Step4: Simplify both sides

Simplifying the left side gives \( x \), and simplifying the right side gives \( 5 \). So we have:

$$ x > 5 $$

Answer:

c. \( x > -10 \)

Second Inequality ($3x - 5 > 10$)