Question

solve the inequality and graph the solution. 3y + 1 > 10 to draw a ray, plot an endpoint and select an arrow. select an endpoint to change it from closed to open. select the middle of the ray to delete it.

Explanation:

Step1: Subtract 1 from both sides

$$3y+1 - 1>10 - 1$$
$$3y>9$$

Step2: Divide both sides by 3

$$\frac{3y}{3}>\frac{9}{3}$$
$$y > 3$$

To graph \(y>3\):

• Plot an open - circle at \(y = 3\) (because the inequality is strict, \(y

eq3\)).

• Draw a ray to the right of \(y = 3\) (since \(y\) values greater than 3 satisfy the inequality).

Answer:

The solution of the inequality \(3y + 1>10\) is \(y>3\). On the number - line, there is an open circle at \(3\) and a ray extending to the right.