Question

solve the inequality.
$-\frac{x}{3} + 2 \geq 1$
$x \leq ?$

Explanation:

Step1: Subtract 2 from both sides

$-\frac{x}{3}+2 - 2\geq1 - 2$
Simplify to get: $-\frac{x}{3}\geq - 1$

Step2: Multiply both sides by -3 (reverse inequality)

$-\frac{x}{3}\times(-3)\leq - 1\times(-3)$
Simplify to get: $x\leq3$

Answer:

3