Question

solve the inequality:
$-3y + 12 > 21$

a $y < -3$

b $y > -3$

c $y < -11$

d $y > -11$

Explanation:

Step1: Subtract 12 from both sides

To isolate the term with \( y \), we subtract 12 from both sides of the inequality \(-3y + 12>21\). This gives us \(-3y+12 - 12>21 - 12\), which simplifies to \(-3y>9\).

Step2: Divide both sides by -3 (and reverse inequality)

When we divide both sides of an inequality by a negative number, we must reverse the direction of the inequality sign. Dividing both sides of \(-3y > 9\) by \(-3\), we get \(y<\frac{9}{-3}\), which simplifies to \(y < - 3\).

Answer:

A. \( y < -3 \)