Question

1. solve the inequality. $4(x + 3) - 7 \geq x + 3(x + 1)$

Explanation:

Step1: Expand both sides

Expand \(4(x + 3)-7\) to get \(4x+12 - 7=4x + 5\). Expand \(x + 3(x + 1)\) to get \(x+3x + 3=4x+3\). So the inequality becomes \(4x + 5\geq4x+3\).

Step2: Subtract \(4x\) from both sides

Subtract \(4x\) from both sides of the inequality \(4x + 5\geq4x+3\), we get \(5\geq3\).

Answer:

The inequality \(5\geq3\) is always true, so the solution is all real numbers, or in interval notation \((-\infty,\infty)\)