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QUESTION IMAGE

solve for y and graph the solution. $y + 20 \\leq 3y + 20$ or $11y - 8 …

Question

solve for y and graph the solution.
$y + 20 \leq 3y + 20$ or $11y - 8 \geq 13y$
plot the endpoints. select an endpoint to change it from closed to open. select the middle of a segment, ray, or line to delete it.
-14 -12 -10 -8 -6 -4 -2 0 2 4
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Explanation:

Step1: Solve first inequality

$y + 20 \leq 3y + 20$
Subtract $y$ and 20: $0 \leq 2y \Rightarrow y \geq 0$

Step2: Solve second inequality

$11y - 8 \geq 13y$
Subtract $11y$: $-8 \geq 2y \Rightarrow y \leq -4$

Answer:

The solution is $y \leq -4$ or $y \geq 0$. For the graph: plot a closed circle at $-4$ with a ray leftward, and a closed circle at $0$ with a ray rightward.