Question

solve for x and graph the solution.
0 ≤ (x + 16)/4 ≤ 3
plot the endpoints. select an endpoint to change it from closed to open. select the middle of a segment, ray, or line to delete it.

Explanation:

Step1: Multiply all parts by 4

$$\begin{align*} 0\times4&\leq\frac{x + 16}{4}\times4\leq3\times4\\ 0&\leq x+16\leq12 \end{align*}$$

Step2: Subtract 16 from all parts

$$\begin{align*} 0-16&\leq x+16 - 16\leq12-16\\ -16&\leq x\leq-4 \end{align*}$$

Answer:

The solution is \(-16\leq x\leq -4\). On the number - line, we plot a closed circle at \(-16\) and a closed circle at \(-4\) and connect them with a line segment.