Question

solve the following system of equations.
6x + 5y = -10
3x + 5y = 20

Explanation:

Step1: Subtract the two equations

Subtract the second equation \(3x + 5y = 20\) from the first equation \(6x + 5y = -10\).

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Step2: Solve for \(x\)

Divide both sides of \(3x = -30\) by 3.

$$ x = \frac{-30}{3} = -10 $$

Step3: Substitute \(x\) into one equation

Substitute \(x = -10\) into the second equation \(3x + 5y = 20\).

$$ 3(-10) + 5y = 20 $$

Step4: Solve for \(y\)

Simplify and solve for \(y\).

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Answer:

\(x = -10\), \(y = 10\)