Question

solve the following system.
\\(\

$$\begin{cases}4x + 3y - z=-8\\-y + 2z = 5\\3z = 9\\end{cases}$$

\\)
x =

y =

z =

Explanation:

Step1: Solve for z

Given $3z = 9$, divide both sides by 3. So $z=\frac{9}{3}=3$.

Step2: Solve for y

Substitute $z = 3$ into $-y + 2z=5$. We get $-y+2\times3 = 5$, which simplifies to $-y+6 = 5$. Then $-y=5 - 6=-1$, so $y = 1$.

Step3: Solve for x

Substitute $y = 1$ and $z = 3$ into $4x+3y - z=-8$. We have $4x+3\times1-3=-8$. This simplifies to $4x=-8$, and then $x=-2$.

Answer:

$x=-2$, $y = 1$, $z = 3$