Question

solve the following compound inequality.
2y + 16 > 20 or 5y - 10 < 65
y > ? or y <

Explanation:

Step1: Solve \(2y + 16>20\)

Subtract 16 from both sides: \(2y+16 - 16>20 - 16\)
Simplify: \(2y>4\)
Divide both sides by 2: \(\frac{2y}{2}>\frac{4}{2}\)
Simplify: \(y > 2\)

Step2: Solve \(5y-10<65\)

Add 10 to both sides: \(5y-10 + 10<65 + 10\)
Simplify: \(5y<75\)
Divide both sides by 5: \(\frac{5y}{5}<\frac{75}{5}\)
Simplify: \(y < 15\)

Answer:

For \(2y + 16>20\), we get \(y>2\); for \(5y - 10<65\), we get \(y < 15\). So the solutions are \(y>2\) OR \(y < 15\). The value in the first box is \(2\) and the value in the second box is \(15\).