Question

solve the following compound inequality.

\\-9 \le 5 + 2x < -5\\

\\? \le x < \quad\\

Explanation:

Subtract 5 from all parts of the inequality

$$ -9 - 5 \le 2x < -5 - 5 $$

$$ -14 \le 2x < -10 $$

Divide all parts by 2

$$ \frac{-14}{2} \le x < \frac{-10}{2} $$

$$ -7 \le x < -5 $$

Answer:

Solve the following compound inequality.

$$-9 \le 5 + 2x < -5$$

<blank>-7</blank> \(\le x <\) <blank>-5</blank>