Question

solve the following compound inequality.
-3 ≤ 5 + 2x < 5
? ≤ x <

Explanation:

Step1: Subtract 5 from all parts

To isolate the term with \(x\), we subtract 5 from each part of the compound inequality.

$$ -3 - 5 \leq 5 + 2x - 5 < 5 - 5 $$

Simplifying each part:

$$ -8 \leq 2x < 0 $$

Step2: Divide all parts by 2

To solve for \(x\), we divide each part of the inequality by 2.

$$ \frac{-8}{2} \leq \frac{2x}{2} < \frac{0}{2} $$

Simplifying each part:

$$ -4 \leq x < 0 $$

Answer:

\(-4 \leq x < 0\) (So the first box is \(-4\) and the second box is \(0\))