Question

1. solve \\(\frac{2}{9}x = 72\\).

a. \\(x = 8\\) c. \\(x = 72\frac{2}{9}\\)
b. \\(x = 324\\) d. \\(x = 16\\)

1. if \\(3x = 21\\), find the value of \\(23 - 4x\\).

a. \\(-5\\) c. \\(2\\)
b. \\(5\\) d. \\(-2\\)

Explanation:

Problem 1

Step1: Isolate \( x \)

To solve \( \frac{2}{9}x = 72 \), multiply both sides by the reciprocal of \( \frac{2}{9} \), which is \( \frac{9}{2} \).
\( x = 72 \times \frac{9}{2} \)

Step2: Calculate the product

Simplify \( 72 \times \frac{9}{2} \). Divide 72 by 2 first: \( 72 \div 2 = 36 \), then multiply by 9: \( 36 \times 9 = 324 \).
So \( x = 324 \).

Step1: Solve for \( x \)

Given \( 3x = 21 \), divide both sides by 3:
\( x = \frac{21}{3} = 7 \)

Step2: Substitute \( x \) into \( 23 - 4x \)

Substitute \( x = 7 \) into \( 23 - 4x \):
\( 23 - 4(7) = 23 - 28 = -5 \)

Answer:

b. \( x = 324 \)

Problem 2