Question

solve the equation by the square root property. 2x^2 + 5 = 19 the solution set is { }. (simplify your answer. type an exact answer, using radicals as needed. use a c as needed.)

Explanation:

Step1: Isolate the quadratic term

Subtract 5 from both sides of the equation $2x^{2}+5 = 19$.
$2x^{2}=19 - 5$
$2x^{2}=14$

Step2: Solve for $x^{2}$

Divide both sides of the equation $2x^{2}=14$ by 2.
$x^{2}=\frac{14}{2}$
$x^{2}=7$

Step3: Apply square - root property

Take the square root of both sides. Remember, if $x^{2}=a$ ($a\geq0$), then $x=\pm\sqrt{a}$.
$x=\pm\sqrt{7}$

Answer:

$\{-\sqrt{7},\sqrt{7}\}$