Question

solve the equation for b.
mb + c = 12

Explanation:

To solve the equation \( mb + c = 12 \) for \( b \), we need to isolate \( b \) on one side of the equation.

Step 1: Subtract \( c \) from both sides

Subtracting \( c \) from both sides of the equation \( mb + c = 12 \) gives:

$$ mb + c - c= 12 - c $$

Simplifying the left - hand side (since \( c - c = 0\)) and the right - hand side, we get:

$$ mb=12 - c $$

Step 2: Divide both sides by \( m \) (assuming \( m

eq0\))
To isolate \( b \), we divide both sides of the equation \( mb = 12 - c\) by \( m\). So we have:

$$ \frac{mb}{m}=\frac{12 - c}{m} $$

Simplifying the left - hand side (since \(\frac{mb}{m}=b\) for \(m
eq0\)), we obtain:

$$ b=\frac{12 - c}{m} $$

The final answer is \( b=\frac{12 - c}{m}\) (for \(m
eq0\)).

Answer:

To solve the equation \( mb + c = 12 \) for \( b \), we need to isolate \( b \) on one side of the equation.

Step 1: Subtract \( c \) from both sides

Subtracting \( c \) from both sides of the equation \( mb + c = 12 \) gives:

$$ mb + c - c= 12 - c $$

Simplifying the left - hand side (since \( c - c = 0\)) and the right - hand side, we get:

$$ mb=12 - c $$

Step 2: Divide both sides by \( m \) (assuming \( m

eq0\))
To isolate \( b \), we divide both sides of the equation \( mb = 12 - c\) by \( m\). So we have:

$$ \frac{mb}{m}=\frac{12 - c}{m} $$

Simplifying the left - hand side (since \(\frac{mb}{m}=b\) for \(m
eq0\)), we obtain:

$$ b=\frac{12 - c}{m} $$

The final answer is \( b=\frac{12 - c}{m}\) (for \(m
eq0\)).