Question

solve the equation for c: -2(c - 4) = -8 a c = -8 b c = 8 c c = 4

Explanation:

Step1: Divide both sides by -2

Divide each side of the equation \(-2(c - 4) = -8\) by \(-2\). So we have \(\frac{-2(c - 4)}{-2}=\frac{-8}{-2}\), which simplifies to \(c - 4 = 4\).

Step2: Add 4 to both sides

Add 4 to both sides of the equation \(c - 4 = 4\). We get \(c-4 + 4=4 + 4\), so \(c = 8\)? Wait, no, wait. Wait, \(\frac{-8}{-2}=4\), so \(c - 4=4\), then add 4 to both sides: \(c=4 + 4=8\)? Wait, but let's check again. Wait, original equation: \(-2(c - 4)=-8\). Let's substitute \(c = 8\): \(-2(8 - 4)=-2\times4=-8\), which matches. Wait, but option B is \(c = 8\), option C is \(c = 4\). Wait, maybe I made a mistake. Wait, let's do it again.

Wait, step 1: Divide both sides by -2: \(\frac{-2(c - 4)}{-2}=\frac{-8}{-2}\) → \(c - 4 = 4\). Then step 2: Add 4 to both sides: \(c=4 + 4=8\). So the solution is \(c = 8\), which is option B. Wait, but let's check option C: if \(c = 4\), then \(-2(4 - 4)=-2\times0 = 0
eq -8\). So option B is correct.

Answer:

B. \(c = 8\)