Question

solve each inequality. then graph the solution set on a number line. 1.) 5 ≥ 7 + y 2.) 11 ≤ p + 4

Explanation:

Step1: Solve the first inequality

Subtract 7 from both sides of $5\geq7 + y$.
$5-7\geq7 + y-7$
$-2\geq y$ or $y\leq - 2$

Step2: Solve the second inequality

Subtract 4 from both sides of $11\leq p + 4$.
$11-4\leq p+4 - 4$
$7\leq p$ or $p\geq7$

Answer:

1. The solution of $5\geq7 + y$ is $y\leq - 2$. To graph it on a number - line, draw a closed circle at - 2 and shade to the left.
2. The solution of $11\leq p + 4$ is $p\geq7$. To graph it on a number - line, draw a closed circle at 7 and shade to the right.