Question

solve $4ax + 5ax = 6ax + 9$ for $x$. assume $a \
eq 0$.\
\
\bigcirc a. $x = \frac{1}{2a}$\
\bigcirc b. $x = 3a$\
\bigcirc c. $x = \frac{3}{a}$\
\bigcirc d. $x = 2a$

Explanation:

Step1: Combine like terms left side

$4ax + 5ax = 9ax$

Step2: Subtract $6ax$ from both sides

$9ax - 6ax = 9 \implies 3ax = 9$

Step3: Solve for $x$ (divide by $3a$)

$x = \frac{9}{3a} = \frac{3}{a}$

Answer:

C. $x = \frac{3}{a}$