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solve for u. 3(u - 7) - 12 ≥ 3

Question

solve for u.
3(u - 7) - 12 ≥ 3

Explanation:

Step1: Expand the left - hand side

$3(u - 7)-12=3u-21 - 12=3u - 33$. So the inequality becomes $3u-33\geq3$.

Step2: Add 33 to both sides

$3u-33 + 33\geq3 + 33$, which simplifies to $3u\geq36$.

Step3: Divide both sides by 3

$\frac{3u}{3}\geq\frac{36}{3}$, so $u\geq12$.

Answer:

$u\geq12$