Question

solve for n.
( n + 1 = 4(n - 8) )
( \bigcirc n = 1 )
( \bigcirc n = 8 )
( \bigcirc n = 11 )
( \bigcirc n = 16 )

Explanation:

Step1: Expand the right-hand side

$n + 1 = 4n - 32$

Step2: Isolate n terms on one side

$1 + 32 = 4n - n$

Step3: Simplify both sides

$33 = 3n$

Step4: Solve for n

$n = \frac{33}{3}$

Answer:

C. $n=11$