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solve for (t). (3(t + 10)-6 < - 15)

Question

solve for (t).
(3(t + 10)-6 < - 15)

Explanation:

Step1: Expand the left - hand side

$3(f + 10)-6=3f+30 - 6=3f + 24$. So the inequality becomes $3f+24\lt - 15$.

Step2: Subtract 24 from both sides

$3f+24-24\lt - 15 - 24$, which simplifies to $3f\lt-39$.

Step3: Divide both sides by 3

$\frac{3f}{3}\lt\frac{-39}{3}$, so $f\lt - 13$.

Answer:

$f\lt - 13$