Question

the solutions to the inequality $y > -3x + 2$ are shaded on the graph. which point is a solution?
$(0, 2)$
$(2, 0)$
$(1, -2)$
$(-2, 1)$

Explanation:

Step1: Check (0, 2)

Substitute \(x = 0\), \(y = 2\) into \(y > -3x + 2\):
\(2 > -3(0) + 2\) → \(2 > 2\), which is false.

Step2: Check (2, 0)

Substitute \(x = 2\), \(y = 0\) into \(y > -3x + 2\):
\(0 > -3(2) + 2\) → \(0 > -4\), which is true.

Step3: Check (1, -2)

Substitute \(x = 1\), \(y = -2\) into \(y > -3x + 2\):
\(-2 > -3(1) + 2\) → \(-2 > -1\), which is false.

Step4: Check (-2, 1)

Substitute \(x = -2\), \(y = 1\) into \(y > -3x + 2\):
\(1 > -3(-2) + 2\) → \(1 > 8\), which is false.

Answer:

(2, 0)