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$-2x + 40 < 38$
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attempt 1 out of 2
inequality notation:
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-12 -10 -8 -6 -4 -2 0 2 4 6 8 10 12
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Step1: Subtract 40 from both sides
Subtract 40 from each side of the inequality \(-2x + 40 < 38\) to isolate the term with \(x\).
\(-2x + 40 - 40 < 38 - 40\)
Simplifying gives: \(-2x < -2\).
Step2: Divide by -2 (reverse inequality)
Divide both sides by \(-2\). When dividing an inequality by a negative number, reverse the inequality sign.
\(\frac{-2x}{-2} > \frac{-2}{-2}\)
Simplifying gives: \(x > 1\).
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Inequality Notation: \(x > 1\)