Question

a solid object in the shape of a rectangular prism is shown below.
if its density is $10.8\frac{\text{kg}}{\text{m}^3}$, what is its mass?
give an exact integer or decimal answer.
be sure to include the correct unit in your answer.
mass $=\square$

Explanation:

Step1: Calculate the volume of the rectangular prism

The volume \( V \) of a rectangular prism is given by \( V = l\times w\times h \). Here, \( l = 6\space m\), \( w = 6\space m\), \( h = 6\space m\). So, \( V=6\times6\times6\).

$$V = 216\space m^{3}$$

Step2: Use the density formula to find the mass

The density formula is \(
ho=\frac{m}{V}\), where \(
ho\) is density, \( m\) is mass, and \( V\) is volume. Rearranging for \( m\) gives \( m=
ho\times V\). Given \(
ho = 10.8\space\frac{kg}{m^{3}}\) and \( V = 216\space m^{3}\), then \( m=10.8\times216\).

$$m = 10.8\times216=2332.8\space kg$$

Answer:

\(2332.8\space kg\)