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1. a soccer ball accelerates more than a bowling ball when thrown with …

Question

  1. a soccer ball accelerates more than a bowling ball when thrown with the same force. this demonstrates.

d. law of inertia
a. newtons 1st law
c. newtons 3rd law
b. newtons 2nd law

  1. imagine a toddler on a swing. which of these best supports newtons first law

a. the child and the swing exert the same amount of force on each others
c. the child will go higher than and adult that is pushed
while sitting on the swing. he wont move until he is pushed by someone
d. the child goes higher the harder he is pushed.

  1. macie enjoys playing lacrosse on the school team. suppose macie throws a lacrosse ball with a force of 6 n, and the resulting acceleration is 43 m/s. what is the mass of the lacrosse ball?

d. 258.0 kg
b. 0.14 m
a. 0.14 kg
c. 7.20 kg

Explanation:

Question 1
Brief Explanations

Newton's 2nd law is \(F = ma\) (force equals mass times acceleration). When the same force \(F\) is applied, a smaller - mass object (soccer ball) has a larger acceleration \(a\) (since \(a=\frac{F}{m}\)) compared to a larger - mass object (bowling ball). The Law of Inertia (Newton's 1st law) is about an object's tendency to stay at rest or in uniform motion. Newton's 3rd law is about action - reaction pairs.

Brief Explanations

Newton's 1st law (Law of Inertia) states that an object at rest will stay at rest unless acted upon by an external force. The child on the swing not moving until pushed is an example of an object at rest (\(v = 0\)) staying at rest until a force (the push) is applied. Option A is Newton's 3rd law (action - reaction). Option C and D are related to Newton's 2nd law (\(F = ma\)).

Step1: Recall Newton's 2nd law formula

Newton's 2nd law is \(F=ma\), where \(F\) is the force, \(m\) is the mass, and \(a\) is the acceleration. We need to solve for \(m\), so we can rewrite the formula as \(m = \frac{F}{a}\).

Step2: Substitute the given values

We are given \(F = 6N\) and \(a=43m/s^{2}\). Substitute these values into the formula \(m=\frac{F}{a}\), so \(m=\frac{6}{43}\approx0.14kg\)

Answer:

B. Newton's 2nd law

Question 2