QUESTION IMAGE
Question
- the slope of the line with equation 6x + 5y - 1 = 0 is
a. $-\frac{6}{5}$
b. $-\frac{5}{6}$
c. $\frac{6}{5}$
d. $\frac{1}{5}$
Step1: Convert to slope - intercept form
The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope. We start with the equation $6x+5y - 1=0$. First, we isolate the $y$ term.
Add $- 6x + 1$ to both sides of the equation: $5y=-6x + 1$.
Step2: Solve for y
Divide each term in the equation $5y=-6x + 1$ by 5.
We get $y=-\frac{6}{5}x+\frac{1}{5}$.
In the slope - intercept form $y = mx + b$, the coefficient of $x$ (i.e., $m$) is the slope. So the slope $m =-\frac{6}{5}$.
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A. $-\frac{6}{5}$