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Question
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- which expression is equivalent to \\(\sqrt{20x^{16}y^{25}}\\) for positive x and y values?
a \\(2x^4y^5\sqrt{5}\\)
b \\(5x^4y^5\sqrt{2}\\)
c \\(2x^8y^{12}\sqrt{5y}\\)
d \\(5x^8y^{12}\sqrt{2y}\\)
Step1: Factor the radicand
$\sqrt{20x^{16}y^{25}} = \sqrt{4 \times 5 \times x^{16} \times y^{24} \times y}$
Step2: Simplify perfect squares
$\sqrt{4} = 2$, $\sqrt{x^{16}} = x^8$, $\sqrt{y^{24}} = y^{12}$; remaining: $\sqrt{5y}$
Step3: Combine simplified terms
$2x^8y^{12}\sqrt{5y}$ (Note: Check options—corrected typo in C: should be $2x^8y^{12}\sqrt{5y}$)
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C. $2x^8y^{12}\sqrt{5y}$