Question

a sled is pushed with 30 n and sliding friction is 10 n. find the net force on the sled.

Explanation:

Step1: Determine the direction of forces

The pushing force \(F_{push}=30N\) is in the forward direction, and the sliding - friction force \(F_{friction}=10N\) is in the opposite (backward) direction.

Step2: Calculate the net force

The formula for net force \(F_{net}\) when two forces act in opposite directions is \(F_{net}=F_{1}-F_{2}\) (where \(F_{1}\) is the larger force and \(F_{2}\) is the smaller force). Here, \(F_{net}=F_{push}-F_{friction}\).
Substitute \(F_{push} = 30N\) and \(F_{friction}=10N\) into the formula: \(F_{net}=30 - 10\).

Answer:

\(20N\)