Question

situations:

1. an infant weighing 12 lb. 4 oz. has a fever and needs tylenol (acetaminophen). determine the minimum and maximum dose to be given. (10 - 15 mg acetaminophen/kg body weight; every 6 - 8 hours)

12 lb → \\(\frac{453.6g}{11b}\times\frac{1kg}{1000g}=\\)

Explanation:

Step1: Convert the weight to kilograms

First, convert 12 lb 4 oz to ounces. Since 1 lb = 16 oz, 12 lb = 12×16 = 192 oz. Then 12 lb 4 oz=192 + 4=196 oz.
Since 1 oz = 28.35 g, the weight in grams is \(m = 196\times28.35=5556.6\) g.
Convert grams to kilograms: \(5556.6\div1000 = 5.5566\) kg.

Step2: Calculate the minimum dose

The minimum dose is \(10\) mg/kg. So the minimum dose \(D_{min}=10\times5.5566 = 55.566\) mg.

Step3: Calculate the maximum dose

The maximum dose is \(15\) mg/kg. So the maximum dose \(D_{max}=15\times5.5566=83.349\) mg.

Answer:

The minimum dose is approximately \(55.6\) mg and the maximum dose is approximately \(83.3\) mg.