Question

simplify.
$\left(\frac{-2y}{z^{2}}\
ight)^{5}$
write your answer without parentheses.

Explanation:

Step1: Apply power - of - a - quotient rule

$(\frac{-2y}{z^{2}})^5=\frac{(-2y)^5}{(z^{2})^5}$

Step2: Apply power - of - a - product rule to $(-2y)^5$

$(-2y)^5=(-2)^5y^5=-32y^5$

Step3: Apply power - of - a - power rule to $(z^{2})^5$

$(z^{2})^5 = z^{2\times5}=z^{10}$

Step4: Combine the results

$\frac{(-2y)^5}{(z^{2})^5}=\frac{-32y^5}{z^{10}}$

Answer:

$\frac{-32y^5}{z^{10}}$