Question

simplify. express your answer using positive exponents.
$\frac{9j^{5}k^{4}}{9j^{3}k}$

Explanation:

Step1: Divide the coefficients

$\frac{9}{9}=1$

Step2: Use the quotient - rule for exponents ($\frac{a^m}{a^n}=a^{m - n}$) for the $j$ terms

$\frac{j^{5}}{j^{3}}=j^{5 - 3}=j^{2}$

Step3: Use the quotient - rule for exponents for the $k$ terms

$\frac{k^{4}}{k}=k^{4 - 1}=k^{3}$

Step4: Combine the results

$1\times j^{2}\times k^{3}=j^{2}k^{3}$

Answer:

$j^{2}k^{3}$