Question

in 8 and 9, simplify each expression. 8. (9x^{2}y^{-3}), for (x = 5) and (y = 3).

Explanation:

Step1: Substitute values of x and y

Substitute $x = 5$ and $y = 3$ into $9x^{2}y^{-3}$. We get $9\times5^{2}\times3^{-3}$.

Step2: Calculate powers

$5^{2}=25$ and $3^{-3}=\frac{1}{3^{3}}=\frac{1}{27}$. So the expression becomes $9\times25\times\frac{1}{27}$.

Step3: Perform multi - plication

$9\times25 = 225$, then $225\times\frac{1}{27}=\frac{225}{27}$. Simplifying $\frac{225}{27}$ by dividing both numerator and denominator by 9, we get $\frac{25}{3}$.

Answer:

$\frac{25}{3}$