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in the similarity transformation of \\( \\triangle abc \\) to \\( \\tri…

Question

in the similarity transformation of \\( \triangle abc \\) to \\( \triangle dfe \\), \\( \triangle abc \\) was dilated by a scale factor of \\( 1/2 \\), reflected across the ?, and moved through the translation .

Explanation:

Step1: Analyze the reflection

Looking at the positions of the triangles, the \(y -\)coordinates of corresponding points change sign. For example, if we consider a general point \((x,y)\) in \(\triangle ABC\) and its corresponding point in \(\triangle DFE\) after reflection. A reflection across the \(x -\)axis changes the sign of the \(y -\)coordinate of a point. The transformation rule for a reflection across the \(x -\)axis is \((x,y)\to(x, - y)\).

Step2: Analyze the translation

Let's assume a point \(A(x_1,y_1)\) in \(\triangle ABC\). After dilation by a scale factor of \(\frac{1}{2}\) and reflection across the \(x -\)axis, we then need to find the translation.
If we consider the center - like movement. Suppose we take a vertex of \(\triangle ABC\). Let's assume after dilation and reflection, we observe the horizontal and vertical shifts.
For a point \((x,y)\) after dilation (\((x,y)\to(\frac{1}{2}x,\frac{1}{2}y)\)) and reflection across the \(x -\)axis \((\frac{1}{2}x,-\frac{1}{2}y)\), and then translation.
If we consider the movement from the lower - left triangle (\(\triangle ABC\)) to the upper - right triangle (\(\triangle DFE\)), we can use the formula for translation \((x,y)\to(x + h,y + k)\).
By comparing the positions of non - origin related vertices (to avoid confusion with dilation center assumptions), we find that the translation rule is \((x,y)\to(x+4,y + 2)\)

Answer:

The first blank: \(x -\)axis. The translation: \((x,y)\to(x + 4,y+2)\)