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for the sequence (a_n = \frac{11}{n + 1}), its first term is its second…

Question

for the sequence (a_n = \frac{11}{n + 1}),
its first term is
its second term is
its third term is
its fourth term is
its 100th term is

Explanation:

Step1: Find the first term

Substitute \(n = 1\) into the sequence formula:

$$a_1 = \frac{11}{1 + 1} = \frac{11}{2}$$

Step2: Find the second term

Substitute \(n = 2\) into the sequence formula:

$$a_2 = \frac{11}{2 + 1} = \frac{11}{3}$$

Step3: Find the third term

Substitute \(n = 3\) into the sequence formula:

$$a_3 = \frac{11}{3 + 1} = \frac{11}{4}$$

Step4: Find the fourth term

Substitute \(n = 4\) into the sequence formula:

$$a_4 = \frac{11}{4 + 1} = \frac{11}{5}$$

Step5: Find the 100th term

Substitute \(n = 100\) into the sequence formula:

$$a_{100} = \frac{11}{100 + 1} = \frac{11}{101}$$

Answer:

its first term is \(\frac{11}{2}\)
its second term is \(\frac{11}{3}\)
its third term is \(\frac{11}{4}\)
its fourth term is \(\frac{11}{5}\)
its 100th term is \(\frac{11}{101}\)