Question

select the correct answer. a jet plane is traveling with a velocity of 720 kilometers/hour due north. there is a crosswind of 40 kilometers/hour from the east. find the resultant velocity and the direction of the jet plane. a. 720 kilometers/hour in the direction of 3.2° west of north b. 720 kilometers/hour due north c. 721 kilometers/hour in the direction of 3.2° west of north d. 520 kilometers/hour in the direction of 45° east of north

Explanation:

Step1: Define velocity vectors

Jet: (0, 720) km/h (north); Wind: (-40, 0) km/h (west)

Step2: Sum components

Resultant: (-40, 720) km/h

Step3: Calculate magnitude

$v = \sqrt{(-40)^2 + 720^2} \approx 721$ km/h

Step4: Find direction

$\tan\theta = 40/720 \approx 0.0556$, $\theta \approx 3.2^\circ$ west of north

Answer:

C. 721 kilometers/hour in the direction of 3.2° west of north