Question

select the correct answer from each drop - down menu. tyson models the outdoor temperature after noon with the function shown on the graph. complete the statements describing this situation. based on the quadratic model, the temperature will be about °f at 6 p.m. the $r^{2}$ value for this quadratic model is 0.82, indicating that this function a good model of the data

Explanation:

Step1: Identify x - value for 6 p.m.

6 p.m. is 6 hours since noon, so \(t = 6\).

Step2: Read temperature from graph

Looking at the graph at \(t = 6\), the temperature \(f(6)\) is approximately 70°F.

Step3: Analyze \(r^{2}\) value

The coefficient of determination \(r^{2}=0.82\). Since \(r^{2}\) is close to 1 (where 1 represents a perfect - fit), it indicates that the function is a good model of the data.

Answer:

Based on the quadratic model, the temperature will be about 70°F at 6 p.m.
The \(r^{2}\) value for this quadratic model is 0.82, indicating that this function is a good model of the data.