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if angle b is congruent to angle e, then $ \triangle abc $ and $ \triangle efd $ are congruent by the asa criterion.
if, then $ \triangle abc $ and $ \triangle efd $ are congruent by the sas criterion.
ab = de
bc = fd
ca = fd
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Accepted Answer

# Explanation:
## Step1: Recall SAS criterion
The SAS (Side - Angle - Side) criterion for triangle congruence states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
## Step2: Analyze the triangles
In $\triangle ABC$ and $\triangle EFD$, we know that $\angle A=\angle D$ (from the markings). For SAS, we need two sides. The side $AC$ in $\triangle ABC$ and $DE$ in $\triangle EFD$ are marked as equal (from the mid - point markings on $AC$ and $DE$). The included angles for the sides $AC$ and $BC$ in $\triangle ABC$ and $DE$ and $FD$ in $\triangle EFD$ should be considered. If $BC = FD$, then in $\triangle ABC$ and $\triangle EFD$, we have $AC=DE$ (from mid - point, assume $AC = 2x$, $DE=2x$), $\angle A=\angle D$, and $BC = FD$.

# Answer:
$BC = FD$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall SAS criterion

Step2: Analyze the triangles

Answer: