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select all the pairs of adjacent angles. ∠kjl and ∠ijl ∠hge and ∠fge ∠f…

Question

select all the pairs of adjacent angles.
∠kjl and ∠ijl ∠hge and ∠fge
∠fgj and ∠fge ∠ijl and ∠ijg

Explanation:

Step1: Recall adjacent angles definition

Adjacent angles share a common side and vertex, and their non - common sides are on opposite sides of the common side.

Step2: Analyze ∠KJL and ∠IJL

∠KJL and ∠IJL share the common side JL and the common vertex J. Their non - common sides JK and JI are on a straight line (since IJK is a straight line), so they are adjacent angles.

Step3: Analyze ∠HGE and ∠FGE

∠HGE and ∠FGE share the common side GE and the common vertex G. Their non - common sides GH and GF are on a straight line (since FGH is a straight line), so they are adjacent angles.

Step4: Analyze ∠FGJ and ∠FGE

∠FGJ and ∠FGE share the common side FG and the common vertex G. Their non - common sides GJ and GE are not on a straight line? Wait, no, let's check again. Wait, actually, ∠FGJ and ∠FGE: the common vertex is G, common side is FG. The other sides are GJ and GE. Wait, but in the diagram, lines EGL and FGH are two lines intersecting at G, and line IJK is parallel? Wait, no, let's re - check. Wait, ∠FGJ and ∠FGE: do they form a linear pair? Wait, maybe I made a mistake. Wait, ∠IJL and ∠IJG: ∠IJL and ∠IJG share the common side IJ and vertex J? Wait, no. Wait, let's re - evaluate each pair:

  • ∠KJL and ∠IJL: As IJK is a straight line, JL is a common side, vertex J. So they are adjacent (form a linear pair, which are adjacent and supplementary).
  • ∠HGE and ∠FGE: FGH is a straight line, GE is common side, vertex G. So adjacent (linear pair).
  • ∠FGJ and ∠FGE: Common vertex G, common side FG. The other sides are GJ and GE. But are they adjacent? Wait, the angle between FG and GJ is ∠FGJ, and between FG and GE is ∠FGE. But GJ and GE are two different lines from G. Wait, maybe not. Wait, ∠IJL and ∠IJG: ∠IJL has sides IJ and JL, ∠IJG has sides IJ and JG. So common side IJ, common vertex J. So they are adjacent. Wait, maybe my initial analysis was wrong. Wait, let's start over.

Adjacent angles: share a common vertex, a common side, and their non - common sides are distinct and lie on either side of the common side.

  1. ∠KJL and ∠IJL:
  • Common vertex: J
  • Common side: JL
  • Non - common sides: JK and JI (which are on a straight line, so they are adjacent (linear pair)).
  1. ∠HGE and ∠FGE:
  • Common vertex: G
  • Common side: GE
  • Non - common sides: GH and GF (on a straight line, adjacent (linear pair)).
  1. ∠FGJ and ∠FGE:
  • Common vertex: G
  • Common side: FG
  • Non - common sides: GJ and GE. Are these two angles adjacent? Let's see, the angle between FG and GJ is ∠FGJ, and between FG and GE is ∠FGE. Since GJ and GE are two different rays from G, and FG is the common side, they are adjacent? Wait, maybe. Wait, no, maybe I messed up. Wait, the line EGL passes through G and J? Wait, the diagram: E - G - J - L? Wait, maybe the line is EGL, with G and J on it. And FGH is a line with F - G - H, and IJK is a line with I - J - K.

So ∠FGJ: vertex G, sides FG and GJ. ∠FGE: vertex G, sides FG and GE. Since GJ and GE are on the same line (EGL), so ∠FGJ and ∠FGE share FG, vertex G, and GJ and GE are on a straight line. So they are adjacent.

Wait, no, ∠IJL and ∠IJG: ∠IJL has sides IJ and JL, ∠IJG has sides IJ and JG. So common side IJ, vertex J. So adjacent.

Wait, maybe the correct pairs are ∠KJL and ∠IJL, ∠HGE and ∠FGE, ∠IJL and ∠IJG, ∠FGJ and ∠FGE? Wait, no, let's check the options given. The options are:

  • ∠KJL and ∠IJL
  • ∠HGE and ∠FGE
  • ∠FGJ and ∠FGE
  • ∠IJL and ∠IJG

Wait, let's analyze each option:

  • ∠KJL and ∠IJL:
  • Common vertex: J
  • Common side: JL
  • Non - common sides: JK and JI (collinear, so adjacent).…

Answer:

The pairs of adjacent angles are $\angle KJL$ and $\angle IJL$, $\angle HGE$ and $\angle FGE$, $\angle FGJ$ and $\angle FGE$, $\angle IJL$ and $\angle IJG$. (If we need to select from the given options, all four pairs are adjacent. But if there is a mistake in my analysis, please re - check the diagram.)