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select all the correct answers. which three pairs of measurements are p…

Question

select all the correct answers.

which three pairs of measurements are possible side lengths for the triangle?

\\(ab = 4\\), \\(bc = 4\sqrt{3}\\)
\\(bc = 2\sqrt{3}\\), \\(ac = 2\\)
\\(ab = 3\\), \\(ac = 3\sqrt{3}\\)
\\(bc = 10\\), \\(ac = 4\sqrt{3}\\)
\\(ab = 7\\), \\(ac = 14\\)
\\(ab = 11\\), \\(bc = 11\sqrt{3}\\)

Explanation:

Identify the properties of the given triangle

The given triangle \(ABC\) is a \(30^\circ\)-\(60^\circ\)-\(90^\circ\) right triangle, where:

  • \(AB\) is the shorter leg (opposite the \(30^\circ\) angle).
  • \(BC\) is the longer leg (opposite the \(60^\circ\) angle).
  • \(AC\) is the hypotenuse (opposite the \(90^\circ\) angle).

The ratio of the side lengths is:

$$ AB : BC : AC = x : x\sqrt{3} : 2x $$

Evaluate each option

  • Option 1: \(AB = 4, BC = 4\sqrt{3}\)

If \(AB = x = 4\), then \(BC = x\sqrt{3} = 4\sqrt{3}\). This is possible.

  • Option 2: \(BC = 2\sqrt{3}, AC = 2\)

If \(BC = x\sqrt{3} = 2\sqrt{3}\), then \(x = 2\), so the hypotenuse \(AC = 2x = 4\). Here \(AC = 2\), which is incorrect.

  • Option 3: \(AB = 3, AC = 3\sqrt{3}\)

If \(AB = x = 3\), then \(AC = 2x = 6\). Here \(AC = 3\sqrt{3}\), which is incorrect.

  • Option 4: \(BC = 10, AC = 4\sqrt{3}\)

If \(BC = x\sqrt{3} = 10\), then \(x = \frac{10}{\sqrt{3}}\), so \(AC = \frac{20}{\sqrt{3}}\). Here \(AC = 4\sqrt{3}\), which is incorrect.

  • Option 5: \(AB = 7, AC = 14\)

If \(AB = x = 7\), then \(AC = 2x = 14\). This is possible.

  • Option 6: \(AB = 11, BC = 11\sqrt{3}\)

If \(AB = x = 11\), then \(BC = x\sqrt{3} = 11\sqrt{3}\). This is possible.

Select the three correct options

The three possible pairs of measurements are:

  1. \(AB = 4, BC = 4\sqrt{3}\)
  2. \(AB = 7, AC = 14\)
  3. \(AB = 11, BC = 11\sqrt{3}\)

Answer:

  • \(AB = 4, BC = 4\sqrt{3}\) (Correct answer)
  • \(BC = 2\sqrt{3}, AC = 2\)
  • \(AB = 3, AC = 3\sqrt{3}\)
  • \(BC = 10, AC = 4\sqrt{3}\)
  • \(AB = 7, AC = 14\) (Correct answer)
  • \(AB = 11, BC = 11\sqrt{3}\) (Correct answer)