Question

your school built an access ramp to the front entrance of the school. the side of the ramp is a triangular wedge. in triangle rmp, - $overline{pr}=156$ inches - $overline{mp}=12.0$ inches - $overline{rm}=156.5$ inches what is the area of the wedge? use the given information to complete the worksheet. area formulas: - parallelogram: $a = bh$ - square: $a = s^{2}$ - triangle: $a=\frac{1}{2}bh$ - trapezoid: $a=\frac{1}{2}h(b_{1}+b_{2})$

Explanation:

Step1: Identificar la base y la altura

La base $b$ del triángulo es $\overline{PR}=156$ pulgadas y la altura $h$ es $\overline{MP} = 12.0$ pulgadas.

Step2: Aplicar la fórmula del área del triángulo

La fórmula del área de un triángulo es $A=\frac{1}{2}bh$. Sustituimos $b = 156$ y $h=12.0$ en la fórmula: $A=\frac{1}{2}\times156\times12.0$.

Step3: Realizar el cálculo

$\frac{1}{2}\times156\times12.0 = 78\times12.0=936$.

Answer:

Base of the Wedge: 156, inches
Height of the Wedge: 12.0, inches
Area of the Wedge: 936, square inches