Question

scale factor = 2
how are the coordinates related?
you can multiply the coordinates of
△abc by □ to find the coordinates
of △abc.

Explanation:

Step1: Analyze the coordinates

We have \(A(4,3)\) and \(A'(8,6)\), \(B(4,0)\) and \(B'(8,0)\).

Step2: Calculate the multiplier

For \(x\)-coordinate of \(A\): \(4\times k = 8\), so \(k=\frac{8}{4}=2\). For \(y\)-coordinate of \(A\): \(3\times k = 6\), so \(k = 2\). For \(x\)-coordinate of \(B\): \(4\times k=8\), \(k = 2\). For \(y\)-coordinate of \(B\): \(0\times k = 0\) (any number multiplied by \(0\) is \(0\), but the non - zero coordinates follow the rule).

Answer:

You can multiply the coordinates of \(\triangle ABC\) by \(2\) to find the coordinates of \(\triangle A'B'C\).