Question

a sample of solid tungsten is heated with an electrical coil. if 30.4 joules of energy are added to a 14.3 - gram sample initially at 22.7 °c, what is the final temperature of the tungsten? answer: °c use the references to access important values if needed for this question. 3 item attempts remaining

Explanation:

Step1: Recall the specific - heat formula

The formula for heat transfer is $Q = mc\Delta T$, where $Q$ is the heat energy added, $m$ is the mass of the substance, $c$ is the specific - heat capacity, and $\Delta T=T_{f}-T_{i}$ is the change in temperature. The specific - heat capacity of tungsten $c = 0.134\ J/(g\cdot^{\circ}C)$.
We want to find $T_{f}$, and we can re - arrange the formula to $T_{f}=T_{i}+\frac{Q}{mc}$.

Step2: Identify the given values

We are given that $Q = 30.4\ J$, $m = 14.3\ g$, $T_{i}=22.7^{\circ}C$, and $c = 0.134\ J/(g\cdot^{\circ}C)$.

Step3: Substitute the values into the formula

First, calculate $\frac{Q}{mc}$:
$\frac{Q}{mc}=\frac{30.4\ J}{14.3\ g\times0.134\ J/(g\cdot^{\circ}C)}=\frac{30.4}{14.3\times0.134}\ ^{\circ}C$.
$14.3\times0.134 = 1.9162$.
$\frac{30.4}{1.9162}\approx15.97^{\circ}C$.
Then, find $T_{f}$:
$T_{f}=T_{i}+\frac{Q}{mc}=22.7^{\circ}C + 15.97^{\circ}C\approx38.7^{\circ}C$.

Answer:

$38.7$