Question

1. a sample of iron has the dimensions of 2 cm x 3 cm x 2 cm. if the mass of this rectangular - shaped object is 94 g, what is the density of iron?

Explanation:

Step1: Calculate the volume of the rectangular iron sample

The formula for the volume \( V \) of a rectangular prism is \( V = l \times w \times h \), where \( l \), \( w \), and \( h \) are the length, width, and height respectively. Given the dimensions \( 2\space cm \times 3\space cm \times 2\space cm \), we substitute these values into the formula:
\( V = 2 \times 3 \times 2 \)
\( V = 12\space cm^3 \)

Step2: Calculate the density of the iron

The formula for density \(
ho \) is \(
ho = \frac{m}{V} \), where \( m \) is the mass and \( V \) is the volume. We know the mass \( m = 94\space g \) and the volume \( V = 12\space cm^3 \) from Step 1. Substituting these values into the formula:
\(
ho = \frac{94}{12} \approx 7.83\space g/cm^3 \)

Answer:

The density of the iron is approximately \( 7.83\space g/cm^3 \)