Question

-s³ - 5st when s = -3 and t = -2

Explanation:

Step1: Substitute values into expression

$-(-3)^3 -5(-3)(-2)$

Step2: Calculate $(-3)^3$

$-(-27) -5(-3)(-2)$

Step3: Compute each term

$27 - 30$

Step4: Final subtraction

$27 - 30 = -3$ Wait correction: Wait $-(-3)^3 = -(-27)=27$; $-5*(-3)*(-2)= -5*(6)= -30$; $27-30=-3$? Wait no wait original expression is $-s^3 -5st$. So $s=-3$, $t=-2$: $-(-3)^3 -5*(-3)*(-2) = -(-27) -5*(6) =27-30=-3$. Oh correct answer is -3.

Step1: Substitute s=-3, t=-2

$-(-3)^3 -5(-3)(-2)$

Step2: Calculate $(-3)^3$

$-(-27) -5(6)$

Step3: Simplify terms

$27 - 30$

Step4: Compute result

$-3$

Answer:

33