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Question
in the right triangle shown, df = ef = 3. how long is de? choose 1 answer: a 3√2 b 3√3 c 6 d 6√2 e 9
Step1: Apply Pythagorean theorem
In right triangle \( \triangle DFE \), by Pythagorean theorem, \( DE^{2}=DF^{2}+EF^{2} \). Given \( DF = 3 \), \( EF = 3 \).
$$
DE^{2}=3^{2}+3^{2}=9 + 9=18
$$
Step2: Solve for \( DE \)
Take square root on both sides: \( DE=\sqrt{18}=\sqrt{9\times2}=3\sqrt{2} \).
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A. \( 3\sqrt{2} \)