Question

as represented by this velocity - time graph, this object is____.a. at rest for several seconds and then moves up a hillb. moving with a constant speed and then acceleratesc. at rest for several seconds, and then speeds upd. at rest for several seconds and then moves forward at constant speede.... nonsense! none of these appropriately describe the objects motion.

Explanation:

• In a velocity - time graph, when the velocity is \(v = 0\) (horizontal line at \(v = 0\) on the graph), the object is at rest.
• When the velocity - time graph has a non - zero constant slope, the object is accelerating. A horizontal line (after the initial rest period) with \(v

eq0\) would mean constant speed. But in this graph, after the initial rest (\(v = 0\) part), the graph has a positive slope (not a horizontal line for non - zero \(v\)).

• Option a: Moving up a hill is not indicated by the graph (graph is about velocity - time, not related to terrain).
• Option b: There is no initial non - zero constant speed (initial \(v = 0\)).
• Option c: After rest (\(v = 0\)), the graph has a positive slope (object is accelerating, which can be thought of as speeding up).
• Option d: After rest, the graph is not a horizontal line (so not constant speed).

Answer:

C. at rest for several seconds, and then speeds up