Question

5 regina and her friend are pushing a broken car. the force of gravity pulls downward with 11,500 n. the ground pushes upward with a force of 11,500 n. regina is pushing south with a force of 260 n, and her friend is pushing south with a force of 195 n. if the force of friction is 395 n, what is the net force on the car? 60 n south 11,500 n, south 23,850 n north 455 n north

Explanation:

Step1: Analyze vertical forces

The force of gravity ($F_g = 11500\ N$ downward) and the normal force ($F_n=11500\ N$ upward). Since $F_g$ and $F_n$ are equal in magnitude and opposite in direction, their resultant is $F_{vertical}=11500 - 11500=0\ N$.

Step2: Analyze horizontal forces

Regina's force ($F_{R}=260\ N$ south), her friend's force ($F_{f}=195\ N$ south), and the friction force ($F_{fric}=395\ N$ north. Let south be the positive direction. The net horizontal force $F_{net - horizontal}=260 + 195-395$.

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Since the result is positive, the direction is south.

Answer:

60 N south