Question

reflect \\( \triangle j k l \\) across the \\( x \\)-axis.

Explanation:

Step1: Find the coordinates of the original points

From the graph, we can see that the coordinates of point \(J\) are \((-1,4)\), the coordinates of point \(K\) are \((-4,2)\), and the coordinates of point \(L\) are \((-3,1)\).

Step2: Apply the reflection rule across the \(x\) - axis

The rule for reflecting a point \((x,y)\) across the \(x\) - axis is \((x,-y)\).
For point \(J(-1,4)\), after reflection, the new coordinates are \(J'(-1,-4)\).
For point \(K(-4,2)\), after reflection, the new coordinates are \(K'(-4,-2)\).
For point \(L(-3,1)\), after reflection, the new coordinates are \(L'(-3,-1)\).

Step3: Plot the reflected points and connect them

Plot the points \(J'(-1,-4)\), \(K'(-4,-2)\) and \(L'(-3,-1)\) on the coordinate plane and connect them to form the reflected triangle \(\triangle J'K'L'\).

Answer:

The reflected triangle \(\triangle J'K'L'\) has vertices \(J'(-1,-4)\), \(K'(-4,-2)\) and \(L'(-3,-1)\)